For the system of capacitors shown in Figure , find the equivalent capacitance (a) between b and c, and (b

For the system of capacitors shown in Figure , find the equivalent capacitance (a) between b and c, and (b) between a and c.

For the system of capacitors shown in Figure , find the equivalent capacitance (a) between b and c, and (b
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When capaciors are in parallel capacity is added up





Net capacity = C =c1+c2





5uF and8uF are parallel, their equivalent C= 5uF+8uF = 13uF





10uF,13uF and 9uF are now in series





The equivalent capacity of entire circuit = is given by





1/C =1/c1+1/c2+1/c3





1/C =1/10+1/13+1/9





C =1170/337 = 3.472*10^-6 F





The equivalent capacitance =C= 3.472*10^-6 F





Charge on each is same and equal to 'q'





q =CV =1.736*10^-4 F





Charge on 10uF=1.736*10^-4 F





Charge on 9uF=1.736*10^-4 F





Total Charge on entire combination=1.736*10^-4 F


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Reply:THIS IS THE CORRECT ANSWER TO THIS EXERCISE:


Cbc= 9 pF+11 pF=20 pF


A) Cbc = 20 pf


B) Cac =8.571 pF


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Reply:There is no figure to see. Are the capacitors in series or are they parallel?